Question

determine the number of moles of sulfur are present in 34.68 of disulfur pentoxide

plz show how you got your answer

Answer 1

Answer:

0.4816 mol S

Explanation:

I'm going to answer this question under the assumption that the question is how many moles of sulfur are present in 34.68 grams of disulfur pentoxide.

The molecular formula of disulfur pentoxide is S₂O₅ (di means two and penta means five).

Now we convert 34.68 g of S₂O₅ into moles, using its molar mass:

• 34.68 g ÷ 144 g/mol = 0.2408 moles S₂O₅

Then we convert moles of S₂O₅ into moles of S, given that there are two moles of S per S₂O₅ mol:

• 0.2408 moles S₂O₅ * $\frac{2molS}{1molS_2O_5}$ = 0.4816 mol S