Question

Find the standard equation of the circle passing through a given point with a given center . Center (6,3) and passing through (0,-1)

Answer 1

The radius of the circle is r = $\sqrt{ (6-0)^{2} + (3-(-1))^{2} } = \sqrt{52} ;$
The standard equation of the circle is $(x-6)^{2} + (y - 3)^{2} = 52;$