Question

RES
Town Q and Town P were 119 km apart. Van drove from
Town Q to Town P at an average speed of 70 km/h. How
much sooner would he have arrived at Town P if he had
travelled at an average speed of 85 km/h instead?
min​

Answer 1

Answer:

18 minutes earlier

Step-by-step explanation:

Given

$Distance =119km$

$Speed\ 1 = 70km/h$

$Speed\ 2 = 85km/h$

Required

Determine how much sooner if traveled at speed 2 instead of speed 1

Speed is calculated as:

$Speed = \frac{Distance}{Time}$

Make Time the subject

$Time= \frac{Distance}{Speed }$

For Speed 1

$Time= \frac{119km}{70km/h}$

$Time= 1.7hr$

For Speed 2

$Time= \frac{119km}{85km/h}$

$Time= 1.4hr$

Calculate the difference

$Difference = 1.7hr - 1.4hr$

$Difference = 0.3hr$

Convert to minutes

$Difference = 0.3*60\ min$

$Difference = 18\ min$

If traveled at 85km/h, the van will arrive 18 minutes earlier