Answer:
[tex]y = \frac{-3}{4}[/tex]
Step-by-step explanation:
[tex]\frac{y}{2} + \frac{1}{4} = \frac{y}{6}[/tex]
Lets take all the variable terms in L.H.S & all the constant terms in R.H.S.
(While taking a term from one side to another side , it's sign changes )
⇒ [tex]\frac{y}{2} - \frac{y}{6} = -\frac{1}{4}[/tex]
Now in L.H.S. , lets solve the fractions and reduce its numerator and denominator .
⇒ [tex]\frac{3y - y}{6} = -\frac{1}{4}[/tex]
⇒ [tex]\frac{2y}{6} = -\frac{1}{4}[/tex]
⇒ [tex]\frac{y}{3} = -\frac{1}{4}[/tex]
Lets multiplying 3 on both the sides .
⇒ [tex]\frac{y}{3} \times 3 = -\frac{1}{4} \times 3[/tex]
⇒ [tex]y = \frac{-3}{4}[/tex]