Respuesta :

Answer:

Option B, False

Step-by-step explanation:

Step 1:  Get the surface area formulas for both shapes

Surface Area Formula for Cone:  [tex]A = \pi * r(r + \sqrt{h^{2} + r^{2}})[/tex]

Surface Area Formula for Cylinder:  [tex]A = 2\pi rh+2\pi r^{2}[/tex]

Step 2:  Plug in the values and solve

Cone:  [tex]A = \pi * r(r + \sqrt{(3r)^{2} + r^{2}})[/tex]

Cone:  [tex]A = \pi r^{2} + \pi \sqrt{10}r^{2}[/tex]

Cylinder:  [tex]A = 2\pi r*r+2\pi r^{2}[/tex]

Cylinder:  [tex]A=4 \pi r^{2}[/tex]

Step 3:  Compare

[tex]\pi r^{2} + \pi \sqrt{10}r^{2}\neq 4 \pi r^{2}[/tex]

They are not equal, therefore the answer is False.

Answer:  Option B, False

Answer:

ok so i just took this on a p 3 x and its true i have a screenshot . i got the question wrong it's definitely true .

Step-by-step explanation:

Ver imagen vnikfar