Answer:
A. 0.56
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
We want to find [tex]P(H \cap DH)[/tex].
We can relate the numbers using [tex]A = H, B = DH[/tex]. So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(DH|H) = \frac{P(DH \cap H)}{P(H)}[/tex]
P(H) = 0.70 , P(DH/H) = 0.80
So
[tex]P(DH \cap H) = P(DH|H)*P(H) = 0.8*0.7 = 0.56[/tex]
The correct answer is given by option A.