Explanation:
1. Find the empirical formula of a compound that has 36.84% of Nitrogen (N), 63.16% of Oxygen (O).
Secondly, Find molar mass of each component: N=14.0067, O=15.9994
Thirdly, convert to moles: N=2.6301698472874, O=3.9476480368014
Then find smallest mole value: 2.6301698472874
Divide all components my smallest value: N=1, O=1.5009099282591
Then divide by fractional component of each mole value: N=1.9963668986866, O=2.9963668986866
Round to closest whole numbers: N=2, O=3
Lastly, combine to get the empirical formula:N2O3