Question

a metal of length 15.01m is heated until it's temperature rise by 60c.if it is new length is 15.05cm ,calculate it linear expansivity
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Answer 1

Answer:

$\alpha = 4.44 * 10^{-5} ^\circ C^{-1}$

Explanation:

Given

$L_1 = 15.01m$

$L_2 = 15.05m$

$\triangle T = 60^\circ C$

Required

Determine its linear expansivity

This is calculated as:

$\alpha = \frac{L_2 - L_1}{\triangle T * L1}$

$\alpha = \frac{15.05m - 15.01m}{60^\circ C* 15.01m}$

$\alpha = \frac{0.04m}{60^\circ C * 15.01m}$

$\alpha = \frac{0.04}{60^\circ C* 15.01}$

$\alpha = \frac{0.04}{900.6^\circ C}$

$\alpha = 0.00004441483^\circ C^{-1}$

$\alpha = 4.441483 * 10^{-5} ^\circ C^{-1}$

$\alpha = 4.44 * 10^{-5} ^\circ C^{-1}$