Question

Solve the following quadratic equation.
(1 - 18)2 = 1
OA
x = 19 and x = 17
OB.
x= -19 and x = .17
OC. x= -19 and x = 17
D.
x = 19 and x=-17

Answer 1

Given:

Consider the given equation is

$(x-18)^2=1$

To find:

The values of x.

Solution:

We have,

$(x-18)^2=1$

Taking square root on both sides, we get

$x-18=\pm\sqrt{1}$

$x-18=\pm 1$

Adding 18 on both sides, we get

$x-18+18=\pm 1+18$

$x=\pm 1+18$

Now,

$x=1+18$ and $x=-1+18$

$x=19$ and $x=17$

Therefore, the correct option is A.