Question

What is the length of the hypotenuse of the triangle when x = 9?
7x +41
5x
The length of the hypotenuse is about
(Round to the nearest tenth as needed.)

I NEED THIS ASAP

Answer 1

Answer:

$H = 53.30$

Step-by-step explanation:

Given

$Side\ 1 = 7x + 41$

$Side\ 2 = 5x$

Required

Determine side x

The hypotenuse (H) is calculated using:

$H^2 = Side\ 1^2 + Side\ 2^2$

$H^2 = (7x + 41)^2 + (5x)^2$

Substitute 9 for x:

$H^2 = (7*9 + 41)^2 + (5*9)^2$

$H^2 = 10816 + 2025$

$H^2 = 12841$

So:

$H = \sqrt {2841$

$H = 53.30$