Question

How does h
(
t
)
=
1
6
t
change over the interval from t
=
–
7
to t
=
–
2
?

Answer 1

Answer:

h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,

if its asking for:

$\int\limits^2_7 {16t} \, dt$

then it's

16(2) - 16(7) = 32 - 112 = -80