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Answer:Given A uniform horizontal beam with a length of 8.00 m and a weight of 200 n is attached to a wall by a pin connection ( allows rotation). Its far end is supported by a cable that makes an angle of 53 degrees with the horizontal. If a 600 n person stands on the beam at 2.00 m from the wall , find the tension in the cable
Now the force acting on the beam are the gravitational force of earth and weight attached to a wall is 200 N which acts at centre. Also force of person standing is 600 N and force exerted is r and tension is T , also torque due to r is zero because it acts at the pivot point. So r = 0
Torque due to tension in the rope is sin 53 x 8.00 x T.
Torque due to force is 2.0 m x 600 N
The weight of beam acts in the centre since the beam is uniform.
So we have
sin 53 x 8.00 x T - 2 m x 600 N - 4 x 200 N = 0
8 .00 x 0.8 x T = 1200 + 800
0.64 T = 2000 N-m
T = 2000 / 0.64
T = 312.5 N
Explanation:
The tension in the cable and the force exerted on the beam by the wall will be 312.5 N and 1200N respectively.
What is force?
Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem is;
L is the length 5.00 m long,
[tex]\rm \theta[/tex] is the angle of 53.0°
d is the distance = 1.50 m
T is the tension in the cable
F is the force exerted on the beam by the wall= ?
Torque due to tension in the rope is
[tex]\rm \tau = 8.00 \times sin 53^0 \times T[/tex]
Force due to the torque will be;
F= 2.0 m x 600 N
F= 1200 N
The net tension is found as on applying the static equilibirium equation;
sin 53 x 8.00 x T - 2 m x 600 N - 4 x 200 N = 0
8 .00 x 0.8 x T = 1200 + 800
0.64 T = 2000 N-m
T = 2000 / 0.64
T = 312.5 N
Hence the tension in the cable and the force exerted on the beam by the wall will be 312.5 N and 1200N .
To learn more about the force refer to the link;
https://brainly.com/question/26115859
