Question

An engineer designs a cylindrical tank to have a capacity of 4356 cubic inches.
The tank has a diameter of d = 18.5 in. What is the height (h) of the tank to the
nearest tenth of an inch?

Answer 1

Answer:

16.2 in.

Step-by-step explanation:

Vol. of cylindrical tank = Bh, where B is the area of the base

Since the base is a circle, B = $\pi r^{2}$

r = 18.5/2 = 9.25  and let's use 3.14 for π

So.  4356 =$3.14(9.25^{2} ) h$

                = 268.66625h

h = 4356/268.66625

h = 16.2134... = 16.2 in to the nearest tenth of an inch