Respuesta :
Answer:
Step-by-step explanation:
π/2 < 4π/5 < π
4π/5 is in Quadrant II
sin(4π/5) = y-coordinate of A
The coordinates is equal to sin(4π/5) = y-coordinate of A.
We need to find the coordinates is equal to sin (4pi/5).
Which trigonometric functions are positive in which quadrant?
In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.
Then, we have π/2 < 4π/5 < π
So, 4π/5 is in Quadrant II
Hence, the coordinates is equal to sin(4π/5) = y-coordinate of A.
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