Question

And air rifle pellet of mass 2 g Is fired into a block of modelling clay mounted on a model railway track. The trunk and modelling clay have a mass of 0.1 kg the truck moves off after the pellet hits the modelling clay with an initial velocity of 0.8 m/s. State the momentum of the pallet just before it hits the modelling clay

Answer 1

Answer:

0.0816 kgm/s

Explanation:

From the question,

Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.

P =(M+m)u...................... Equation 1

Where P =  initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck

Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg

Substitute these values into equation 1

P = (0.002+0.1)0.8

P = (0.102)0.8

P = 0.0816 kgm/s