Question

Heating Curve Question
How much energy is required to raise the temperature of 88 grams of water at 48°C to steam at 138°

Answer 1

Answer:

Q = 33105.6 J

Explanation:

Given that,

Mass of water, m = 88 grams

The temperature raised from 48°C to steam at 138°.

We need to find the energy required to raise the temperature. The formula for the energy required is given by :

$Q=mc\Delta T$

Where

c is specific heat of water, c = 4.18J/g °C

So,

$Q=88\times 4.18\times (138-48)\\\\Q=33105.6\ J$

So, the required energy is 33105.6 J.