Question

2.00 L of a gas is collected at 25.0°C and 745.0 mmHg. What is the volume at 760.0 mmHg

and 273K. someone help i only have 2 mins left

Answer 1

Answer:

1.79 L

Explanation:

Step 1: Given data

• Initial volume of the gas (V₁): 2.00 L

• Initial temperature of the gas (T₁): 25.0 °C

• Initial pressure of the gas (P₁): 745.0 mmHg

• Final volume of the gas (V₂): ?

• Final temperature of the gas (T₂): 273 K

• Final pressure of the gas (P₂): 760.0 mmHg

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C + 273.15

K = 25.0 °C + 273.15 = 298.2 K

Step 3: Calculate the final volume of the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 745.0 mmHg × 2.00 L × 273 K / 298.2 K × 760.0 mmHg = 1.79 L