Question

Two butterflies simultaneously leave an aster flowerbed and fly to a rose flowerbed. One butterfly flies 10 m/min faster than the other, and so lands on a rose 1 minute earlier. Find the speed of each butterfly if the flowerbeds are 560m apart

Answer 1

The speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

Represent the speed of the first butterfly with x.

Given that the flowerbeds are 560 meters apart, and rate of one butterfly is 10m/min greater than the other

Then, we have:

$B_1 = \frac{560}{x}$

$B_2 = 1 + \frac{560}{x+10}$

Equate both equations

$1 + \frac{560}{x+10} = \frac{560}{x}$

Using a graphing calculator, we have:

$x = 70$

Also, we have:

$x + 10 = 80$

This means that, the speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

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