Question

Which is true for the following equation?
f(x) = −4x2 + 6x − 7
A) The graph opens up and the vertex is a maximum.
B) The graph opens up and the vertex is a minimum.
C) The graph opens down and the vertex is a maximum.
D) The graph opens down and the vertex is a minimum.

Answer 1

Answer:

C) The graph opens down and the vertex is a maximum.

Step-by-step explanation:

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Answer 2

Option (C) will be the correct option.

Properties of a quadratic equation:

• If a quadratic function has been given as,

         f(x) = ax² + bx + c

         Vertex of the parabola is represented by $[-\frac{b}{2a}, f(\frac{b}{2a})]$

         And the sign of the leading coefficient decides the opening of the

         parabola.

         For positive sign of 'a' → Parabola will open upwards

         For negative sign of 'a' → Parabola opens downwards

Quadratic function given in the question is,

f(x) = -4x²+ 6x - 7

Leading coefficient → (-4)

Negative sign represents the opening of the parabola downwards.

And the vertex will be a maximum.

           Therefore, Option (C) will be the correct option.

Learn more about the quadratic function here,

https://brainly.com/question/1979559?referrer=searchResults