Question

What pressure is required to compress 196.0 liters of air at 1.00 atmosphere into a cylinder whose volume is 26.0 liters?

Answer 1

Answer:

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is  

V

1

and its pressure is  

P

1

. Let us suppose that its volume has been increased to  

V

2

, the as per the Boyle's law its pressure will decrease and let us assume the new pressure is  

P

2

.

P

1

 

V

1

=

P

2

V

2

P

1

= 1 atm

V

1

= 196 L

P

2

= ?

V

2

= 26 L substitute the values;

1 atm x 196 L =  

P

2

x 26 L

P

2

= 1 atm x 196 L / 26 L

P

2

= 196 atm L / 26 L = 7.53 atm

Explanation:

I hope this helps.

Answer 2

Answer:

7.53 atm

Explanation:

Boyle studied the relationship between the pressure of a trapped gas and its volume. The data obtained by him shows that the product of pressure and volume for the trapped air sample is constant at a constant temperature.  if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is  V 1  and its pressure is  P 1 . Let us suppose that its volume has been increased to  V 2 , the as per the Boyle's law its pressure will decrease and let us assume the new pressure is  P 2 .  P 1   V 1  = P 2 V 2  P 1  = 1 atm V 1  = 196 L P 2  = ? V 2 = 26 L substitute the values;  1 atm x 196 L =  P 2  x 26 L  P 2  = 1 atm x 196 L / 26 L  P 2  = 196 atm L / 26 L = 7.53 atm