Using relations in a right triangle, it is found that the distance between Q and T is given by:
[tex]h = 32\sqrt{2}[/tex]
The relations in a right triangle are given as follows:
Researching the problem on the internet, it is found that:
Hence:
[tex]\sin{45^\circ} = \frac{32}{h}[/tex]
[tex]\frac{\sqrt{2}}{2} = \frac{32}{h}[/tex]
[tex]h = \frac{64}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}[/tex]
[tex]h = 32\sqrt{2}[/tex]
More can be learned about relations in a right triangle at https://brainly.com/question/26396675