Question

128= 4^2x times 2^x
What is x?

Answer 1

Answer:

x=7/5

Step-by-step explanation:

We can write it in exponential form

128= 2^2*2x * 2^x

2^4x+x=5x

2^5x=128

2^5x=2^7

5x=7

x=7/5

Answer 2

The value of x in the equation given is

$\frac{7}{5}$

To solve :

$128 = {4}^{2x} \times {2}^{x}$

Change all values to have the same root :

${2}^{7} = {2}^{2(2x)} \times {2}^{x}$

${2}^{7} = {2}^{4x} \times {2}^{x}$

${2}^{7} = {2}^{(4x + x)}$

${2}^{7} = {2}^{5x}$

The roots cancel out

$7 = 5x$

Divide both sides by 5

$x = \frac{7}{5}$

Therefore, the value of

$x = \frac{7}{5}$

Learn more : https://brainly.com/question/24617224