Question

Select the correct answer.
On average, Adrian's salary is 1.05 times the previous year's salary.
If Adrian Initially has $52,000 and n denotes the number of years, which recursive equation gives Adrian's annual income, f(n), as a function
the year?
O A. f(1) = 52,000
f(n) = 1.05 · (n − 1), for n > 2
OB. f(1) = 52,000
= 1.05 + f(n - 1), for n > 2
OC (1)
= 1.05
f(n) = 52,000 . f(n − 1), for n > 2
OD.
f(1) = 1.05
f(x) = 52,000 + f(n - 1), for n > 2

Answer 1

Answer: Answer A on Edmentum

Step-by-step explanation:

Answer 2

The correct option is First option i.e. f(1) = 52,000; f(n) = 1.2 · f(n - 1) - 0.30 · f(n - 1) + 2,300; for n ≥ 2

What is Percentage?

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

On average, his salary is 1.2 times the previous year's salary:

f(n)=1.2 X f(n-1)

30% of his income is budgeted for rent:

Rent: R = 30%f(n-1)

           = 30 X f(n-1)/100

        R = 0.30 X f(n-1)

In addition to his salary, Adrian's income increases by $2,300 each year as a result of gifts from family members:

Gifts: G=2,300

If Adrian initially has $52,000:

n=1, f(n)=f(1)=52,000

If n denotes the number of years, which recursive equation gives Adrian's annual income as a function of the year, f(n)?

f(1)=52,000

f(n)=1.2 X f(n-1)-R+G; for n ≥ 2

f(n)=1.2 X f(n-1)-0.30*f(n-1)+2,300; for n ≥ 2

Thus, the correct option is First option i.e. f(1) = 52,000; f(n) = 1.2 · f(n - 1) - 0.30 · f(n - 1) + 2,300; for n ≥ 2

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