Question

Stephen rolls a fair dice 78 times. How many times would Stephen expect to roll a number greater than 2?

Answer 1

Answer:

52 times

Step-by-step explanation:

Given

$n = 78$ -- Number of times

Required

Determine the expected times to get > 2.

In a fair dice, the outcome > 2 are:

$>2 = \{3,4,5,6\}$

The probability of the above is:

$p = \frac{4}{6}$

$p = \frac{2}{3}$

The number of times is calculated using:

$E(x) = n * p$

$E(x) = 78* \frac{2}{3}$

$E(x) = \frac{78* 2}{3}$

$E(x) = \frac{156}{3}$

$E(x) = 52$