Question

& Oregonians eat about 9503 metric tons of food each day. What is this consumption rate in grams
per second?

Answer 1

Answer:

109988 grams per second

Explanation:

To solve this problem first we convert 9503 metric tons into grams, keeping in mind that:

• 1 metric ton = 1000 kg

• 1 kg = 1000 g

Meaning that:

• 9503 metric ton * $\frac{1000kg}{1metricTon}*\frac{1000g}{1kg}$ = 9503x10⁶ g

Then we calculate how many seconds are there in one day:

• 1 day * $\frac{24h}{1day} *\frac{60min}{1h} * \frac{60s}{1min}$ = 86400 s

Finally we calculate the consumption rate:

• 9503x10⁶ g / 86400 s = 109988 g/s