Question

Given the following equation: 3Cl2 (g) + 8NH3 (g) → N2 (g) +
6NH4Cl (s)
How many moles of NH3 are required to produce 12 moles of NH4CI?

Answer 1

Answer:

16 mol

Explanation:

                                 3Cl2 (g) + 8NH3 (g) → N2 (g) + 6NH4Cl (s)    

from reaction                             8 mol                        6 mol

given                                           x mol                       12 mol

8 : x = 6 :12

6x = 12*8

x = 12*8/6 =16 mol