Answer:
1. The work done by the wind was 2.475 x 20^8 J.
The wind’s power was 4.4 x 10^5 W.
F = 3.50 x 10^4 N
S = 20.0 km = 20^4 m
W = 3.50 x 10^4 N x 20^4 m x cos 45 = 3.960 x 10^9 J
2.5 h = 9000 s
3.960 x 10^9/9000 = 4.4 x 10^5
2. If the lever is 100% efficient, the worker needs to push his side 0.735 m.
efficiency = work output/work input x 100
100 = 1250 x 0.1/170d x 100
100/100 = 125/170d
1 = 125/170d
170d = 125
d = 125/170
d = 0.735 m
3. work = force x distance
work = 620 x 15 = 9300 J
work = (160)(9.8)(2.50) = 3920 J
160 x 9.8 = 1568 N
1568/620 = 2.529
mechanical advantage = 2.529
(3920/9300) x 100% = 42.151
efficacy = 42.15%