Question

2KMnO4 + 16HCl -> 5Cl2 + 2KCl + 2MnCl2 + 8H2O If 6.0 moles of KCl are produced, how many moles of HCl were reacted?

Answer 1

Answer:

Explanation:

You just use the balance mole numbers from the equation.

moles HCl needed/16 from the balanced equation ==> 6KCl/2 from equation

x / 16 = 6/2            Multiply both sides   by 16

x = 16 * 6 / 2

x = 48

You need 48 mols of HCl