Answer:
0.020
Step-by-step explanation:
Given that,
μ = 17,
σ = 0.7,
x¯ = 16.7 hours
n(number of batteries) = 30
To find,
The probability(e) by using μ\frac{σ}{[tex]\sqrt{n}[/tex]} = normal cdf
∵ (E - 99, 16.7 , 17, 0.8/[tex]\sqrt{30}[/tex])
The probability of getting a random sample of 30 batteries = 0.020
Hence, the claim is reasonable as only 2% of batteries are likely to last till 16.7 hours.