Question

Three lions and three tigers are walking in a row to get ice cream. The lions are fighting so they are not walking next to each other. in how many different ways can the three lions and three tigers walk if no two lions are the same and no two tigers are the same?

Answer 1

Answer:

72

Step-by-step explanation:

As 3 lions & 3 tigers are to be arranged in a way that lions are not together. It can be done as per following arrangements

LTLTLT , or TLTLTL

Lions can be positioned in six ways, Tigers can also be positioned in 6 ways. There are two alternative positions.

Hence the arrangement can be done in 2 x 6 x 6 = 72 ways  

Answer 2

The different ways should be 72.

calculation:

As 3 lions & 3 tigers are to be arranged

So, it can be

LTLTLT , or TLTLTL

Now the arrangement should be

$= 2 \times 6 \times 6$

= 72 ways  

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