Question

What is the distance between the points (2, 3) and (5, -4)?
7.6 units
3.7 units
6.3 units
10 units

Answer 1

Answer:

Step-by-step explanation:

$d^2=(x_2-x_1)^2+(y_2-y_1)^2\\ \\ d^2=(5-2)^2+(-4-3)^2\\ \\ d^2=3^2+(-7)^2\\ \\ d^2=9+49\\ \\ d^2=58\\ \\ d=\sqrt{58}\\ \\ d\ approx 7.6\ units$