Answer:
0.389 M
Explanation:
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 g
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5 g
Number of mole of CuCl₂ =?
Mole = mass / Molar mass
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Number of mole of CuCl₂ = 0.584 mole
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389 M
The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
The molarity of a solution can be calculated
From the question given above, the following data were obtained:
Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5g
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 moles
The determine the molarity of the solution. This can be obtained as follow:
Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389M
Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
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