Question

If 25.00 mL of 6.00 M HCl is transferred by pipet into a volumetric flask and diluted to 5.00 L, what is the molarity of the diluted HCl?

Answer 1

Answer:

0.03 M

Explanation:

The computation of the molarity of the diluted HCI is given below:

As we know that

(M1) × (V1) = (M2) × (V2)

Now

(M2) = {(M1) × (V1)} ÷ (V2)

or

Molarity of the diluted HCl,(M2) is

= {6 × 25} ÷ 5000

= 0.03 M