A) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
B) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
C) Calculate the percent by mass of a solution made from 15 g NaCl (the solute) and 69 g water.
D) What percent of 73.0 g is 26.1 g?

A-B) In this case, since the total mass of the mixture is 3.02 g and 1.43g+1.41g=2.84 g are recovered in total, we can compute the percent recovery as shown below:

[tex]\%rec=\frac{2.84g}{3.02g}*100\%\\\\\%rec=94\%[/tex]

C) Here, since the solution is made up of NaCl and water, we can say that the mass of the solution is 15g+69g=84g; thus, the percent by mass would be:

[tex]\%=\frac{15g}{84g}*100\%\\\\\%=17.9\%[/tex]

D) In this case, we simply divide 26.1 g by 73.0 g in order to obtain the percent:

[tex]\%=\frac{26.1g}{73.0g}*100\%\\\\\%=35.8\%[/tex]

Best regards!

adioabiola adioabiola · Answer 2 · 2021-11-30T16:59:26+01:00

The percentage in the cases are as follows;

A and B is; 94%
C is; 17.9%
D is; 35.8%

Questions A and B are similar and can be solved as follows;

The total mass of the mixture is 3.02g.
The recovered mass = 1.43g + 1.41g = 2.84g

% recovery = (2.84/3.02) × 100%

% recovery = 94%

Question C can be solved as follows;

Total mass of solution = 15 + 69 = 84g
Mass of solute = 15g

% by mass = (15/84) × 100%

% by mass = 17.9%

Question D can be solved as follows;

% = (26.1/73) × 100%
% = 35.8%