Question

If the mass of the object doubles then the acceleration is when the force is kept the same

Answer 1

Answer:

Halved

Explanation:

F=ma

Let case 1 (original) be:

$F_{1}=m_{1} a_{1}$

Case 2 (new) be:

$F_{2}=m_{2} a_{2}$

Mass is double:

$m_{2}= 2m_{1}$

Force kept the same:

$F_{1} =F_{2}$

Combine the equation and gives:

$\frac{F_{1} }{F_{2}} =\frac{m_{1} a_{1} }{m_{2}a_{2} }\\\frac{F_{1} }{F_{1}} =\frac{m_{1} a_{1} }{2m_{1}a_{2} }\\1=\frac{a_{1} }{2a_{2} }\\a_{2}=\frac{1}{2} a_{1}$

Acceleration is halved