Question

John is 5 years older than Mary. In 10 years, twice John's age decreased by Mary's age is 35, and John's age will be
twice Mary's current age. Find their ages now.
If x is Mary's age now and yis John's age now, which system of equations could not be used to solve the problem?

Answer 1

Answer:

M=15

J=20

Step-by-step explanation:

Let J and M be the present age of John and Mary respectively:

J=M+5

2(J+10)−(M+10)=35

2(M+5+10)−(M+10)=35

2M+30−M−10=35

M=15

J=20