Question

4. Consider the following reaction:
A student performs a neutralization reaction at 298 K according to the following reaction:
NaHCO3 (8) + HCH,O2 (aq) → H20 (1) + CO2 (g) + NaC,H3O2 (aq)
The student adds 1.85 g of solid NaHCO3 into a flask containing 75.0 mL of 0.90 M HCH:02. The student
observes the formation of gas bubbles and also that the flask gets cooler to the touch as the reaction proceeds.
Considering all of the students observations that the student made, is the reaction thermodynamically favorable
at all temperatures, no temperatures, high temperatures or low temperatures. Justify (explain) your selection in
terms of AG

Answer 1

Answer:

High temperatures

Explanation:

NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)

As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).

As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).

In terms of ΔG:

• ΔG = ΔH - TΔS

In order for the reaction to be thermodynamically favorable, ΔH has to be negative, thus:

• The reaction is favorable if TΔS > ΔH.

The greater the temperature, the easier it would be for TΔS to be greater than ΔH.