Question

(points on a circle) PLEASE HELP THIS IS DUE TONIGHT
A circle is centered at C(0,0)C(0,0)C, left parenthesis, 0, comma, 0, right parenthesis. The point M(0,\sqrt{38})M(0,38 )M, left parenthesis, 0, comma, square root of, 38, end square root, right parenthesis is on the circle.

Where does the point N(-5,-3)N(−5,−3)N, left parenthesis, minus, 5, comma, minus, 3, right parenthesis lie?

Answer 1

Answer:

Inside the circle, a distance of $\sqrt{34}$ from the center of the circle.

Step-by-step explanation:

Center of circle is at (0,0)

One point of the circle is at (0,$\sqrt{38}$)

Since the only known point is in the y-axis, the radius of the circle must be $\sqrt{38}$.

$\sqrt{38}$ = 6.164

So the point (-5,-3) is still inside the circle as the distance from point (-5,-3) to the center of the circle is $\sqrt{(5)^2+(-3)^2}$ or $\sqrt{34}$ which is less than the radius of the circle.

Answer 2

Answer: inside the circle, I answered on khan, and have a picture to prove it, see below

Step-by-step explanation: