Respuesta :

Answer:

V = 0.25 x 22.4 Liters

Explanation:

1 mole of any gas occupies 22.4 Liters at STP.

Taking into account the STP conditions, the volume occupied by 0.25 mol of sulfur dioxide at STP is 5.6 L.

First of all, STP conditions is the abbreviation for Standard Temperature and Pressure. The standard temperature is 273 K (0 ° Celsius or 32 ° Fahrenheit) and the standard pressure is 1 atm of pressure and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

On the other hand, the rule of three is a tool that allows you to quickly solve proportionality problems.

To apply a rule of three, 3 pieces of information are needed, from which a fourth piece of information is calculated.

If the relationship between the magnitudes is direct, the rule of three must be applied. In this case, the following formula must be followed, knowing a, b and c and where x is the value to be calculated:

In this case, the rule of three is applied as follows: if by STP conditions, 1 mole of the gas occupies 22.4 L, 0.25 mole will occupy how much volume?

[tex]volume=\frac{0.25 moles*22.4 L}{1 mole}[/tex]

Solving:

volume= 5.6 L

In summary, the volume occupied by 0.25 mol of sulfur dioxide at STP is 5.6 L.

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