A small company shows the profits from their business with the function ​P(x)0.01x^2+60x-​500, where x is the number of units they sell and P is the profit in dollars.
a. How many units are sold by the company to earn the maximum​ profit?
b. Between which numbers of units sold does the company show a​ profit?

Respuesta :

Answer:

A, 3,000 B 8,5992

Step-by-step explanation:

:)

The number of units is 3000 and the profit is $89500 if the profits from their business with the function ​P(x)= -0.01x²+60x-​500, where x is the number of units they sell and P is the profit in dollars.

What are maxima and minima?

Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We are assuming the function is:

P(x) = - 0.01x²+60x-​500

P'(x) = -0.02x + 60

P'(x) = 0

x = 3000

P''(x) = 0.02

P''(x) > 0 for all x

The function is maximum at x = 3000

Plug x = 3000 in the function;

P(3000) = $89500

Thus, the number of units is 3000 and the profit is $89500 if the profits from their business with the function ​P(x)= -0.01x²+60x-​500, where x is the number of units they sell and P is the profit in dollars.

Learn more about the maxima and minima here:

brainly.com/question/6422517

 

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