Answer:
Step-by-step explanation:
[tex]\text{The yellow area is half of the area of the square minus the area of the circle.}\\ \\ A_s=6^2=36\\ \\ A_c=\pi r^2=\pi 3^2=9\pi \\ \\ A_y=\frac{1}{2}(36-9\pi)\approx 3.9in^2[/tex]
Multiply 6 × 6 That's your answer
