Given : A coin is tossed two times successively.
Solution:
Formula used: Probability = [tex]\frac{\text{number of outcome}}{\text{total number of outcome}}[/tex]
(i) Sample space
[tex]HH\\HT\\TH\\TT\\[/tex]
(ii) P( getting exactly one head) = [tex]\frac{2}{4}= \frac{1}{2}[/tex]
(iii) P( getting no heads)=[tex]\frac{1}{4}[/tex]
(iv)P( getting at least one tail)=[tex]\frac{3}{4}[/tex]