Answer:
The pH of the buffer is 7.0 and this pH is not useful to pH 7.0
Explanation:
The pH of a buffer is obtained by using H-H equation:
pH = pKa + log [A⁻] / [HA]
Where pH is the pH of the buffer
The pKa of acetic acid is 4.74.
[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles
[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles
Replacing:
pH = 4.74 + log [0.1779mol] / [0.001mol]
pH = 6.99 ≈ 7.0
The pH of the buffer is 7.0
But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,
this pH is not useful to pH 7.0
