Respuesta :
Answer:
65^2 + 72^2 = hypotenuse^2 = 9409
hypotenuse = 97
65 + 72 + 97 = 234 m perimeter
234 x 12 = 2808 cost per one row
2808 x 4 = 11,232 cost per 4 rows
Given :
▪︎A plot of land is in the shape of a right angled triangle.
▪︎Length of base of triangle = 65 m
▪︎Length of perpendicular of the triangle = 72 m
We know that :
[tex]\color{hotpink} \tt {hypotenuse}^{2} \color{plum}= {height}^{2} + {base}^{2} [/tex]
The hypotenuse or length of the third side :
[tex] = \tt{h}^{2} = {65}^{2} + {72}^{2} [/tex]
[tex] = \tt {h}^{2} = 4225 + 5184[/tex]
[tex] = \tt {h}^{2} = 9409[/tex]
[tex] =\tt h = \sqrt{9409} [/tex]
[tex]\hookrightarrow \tt \color{plum}h = 97 \: m[/tex]
Thus, the length of the hypotenuse of the plot = 97 m
Perimeter of the plot :
[tex] =\tt side + side + side[/tex]
[tex] = \tt65 + 72 + 97[/tex]
[tex] \color{plum}=\tt 234 \: m[/tex]
Thus, the perimeter of the plot = 234 m
Boundary of the plot is made by = 4 wires
Length of wire needed :
[tex] =\tt 234 \times 4[/tex]
[tex]\color{plum} =\tt 936 \: m[/tex]
Thus, quantity of wire needed = 936 m
Cost of 1 m of wire = Rs.12
Cost of 936 m of wire :
[tex] = \tt936 \times 12[/tex]
[tex] \color{plum}=\tt\bold{Rs. \: 11232}[/tex]
Therefore :
▪︎The total cost of wire = Rs.11,232