Answer:
[tex]\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {0.34} & {34\%} &{5-6}& {50} & {0.32} & {32\%} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {} & {} &{5-6}& {50} & {} & {} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}[/tex]
Required
Fill in the gaps
First, we calculate the total frequency:
[tex]Total = \sum f[/tex]
[tex]Total = 29+53+50+22+1[/tex]
[tex]Total = 155[/tex]
The proportion (p) is calculated by:
[tex]p = \frac{f}{Total}[/tex]
The percentage (P) is calculated by:
[tex]P = p * 100\%[/tex]
For interval 7 - 8, we have:
[tex]p = \frac{53}{155} = 0.34[/tex]
[tex]P = 0.34 * 100\% = 34\%[/tex]
For interval 5 - 6, we have:
[tex]p = \frac{50}{155} = 0.32[/tex]
[tex]P = 0.32 * 100\% = 32\%[/tex]
So, the complete table is:
[tex]\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {0.34} & {34\%} &{5-6}& {50} & {0.32} & {32\%} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}[/tex]