Question

(will give brainliest! pls help :))

To make your shot, you need the cue ball to hit point C. Find length CD and use it to identify the location of C in relation to one of the corner pockets. For example, if C is on the upper bumper, your answer might be: 15 inches to the right of the upper left pocket. Round your answer to the nearest inch. (2 points: 1 point for distance, 1 point for location)

Answer 1

Answer:

Step-by-step explanation:

CD should be a perpendicular line to CB.

Angle of incidence = Angle of reflection:

Angle ACD = Angle EAC

Let the perpendicular intersection point from A to side be G

The two right-angled triangles, CDG and CAG, are similar by AAA.

So DG/AG = CD/CA

46/18 = CD/CA

CD+CA = 96-50 = 46

CA = 46-CD

46/18 = CD/(46-CD)

46*46 - 46CD = 18CD

64CD = 46*46

CD = 33.06 = 33in

Answer 2

Answer:

Step-by-step explanation:

let distance between C n hole B be x

triangle CBE is similar to triange formed by the cue ball and the nearest pt on the upper bumper.

DE / BC = cue ball to bumper / C to bumper

46/x = 18/(46-x)

46*46 - 46x = 18x

64x = 2116

x = 33in