Answer:
Molecular Formula: C6H11NaO2
Parent Compound: CID 8892 (Hexanoic acid)
Explanation:
When a mixture of 1−hexanol and hexanoic acid in diethyl ether is shaken with an aqueous NaHCO 3 solution, Hexanoic acid will react with NaHCO 3 to form sodium hexanoate.
CH 3 −CH 2 −CH 2 −CH 2 −CH 2−COOH+NaHCO 3→CH 3−(CH 2 ) 4 −COONa+H 2 O+CO 2
