Question

A man flies a kite with a 100 foot string the angle of elevation of the string is 52 how high off the ground is the kite

Answer 1

Answer:

          About  78.8 ft

Step-by-step explanation:

$\sin52^o=\dfrac H{100}\\\\H=100\sin52^o\\\\H\approx78.8\ ft$

Answer 2

The height of the kite above the ground will be 78.8 feet.

What is the height?

The height is a vertical distance between two points.in the question. It is given that a man flies a kite with a 100-foot string the angle of elevation of the string is 52.

The height of the kite will be calculated by the right-angle property.

SinФ = h /  100

Sin 52°= h / 100

h  =  100 x Sin52°

h = 78.8 feet.

Therefore the height of the kite above the ground will be 78.8 feet.

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