Answer:
199.2J
Explanation:
To calculate the the amount of energy stored in a capacitor, we use the following formula;
W = ½ QV
Where;
W = energy stored (joules)
Q = charge (Coulombs)
V = voltage (volts)
According to the information provided in this question, the capacitor of a camera flash unit has a charge (Q) of 0.83 C and a voltage (V) of 480 V.
Using W = ½ QV
W = ½ × 0.83 × 480
W = ½ × 398.4
W = 398.4/2
W = 199.2
The amount of energy stored in the capacitor to convert electrical energy into light energy is 199.2J.
