Answer:
The error is;
B. Kimberly did not find the inverse sine of the value she calculated
Step-by-step explanation:
The given parameters of the triangle ΔLMN are;
[tex]\overline {LN}[/tex] = 16
[tex]\overline {NM}[/tex] = 10
∠L = 33°
By sine rule, we have;
[tex]\dfrac{sin \ M}{16} = \dfrac{sin \ L}{10} = \dfrac{sin \ N}{\overline {LM}}[/tex]
Given that ∠L = 33°, we have;
[tex]\dfrac{sin \ M}{16} = \dfrac{sin \ 33^{\circ}}{10}[/tex]
Therefore, we have;
[tex]sin \ M = 16 \times \dfrac{sin \ 33^{\circ}}{10} \approx 0.8714[/tex]
sin M ≈ 0.8714
[tex]\therefore m \angle M = sin^{-1} \, (sin \ M)\approx sin^{-1} (0.8714) \approx 60.62^{\circ}[/tex]
Therefore, m∠M ≈ 60.62°
m∠M ≠ sin M ≈ 0.8714
Therefore;
Kimberly did not find the inverse sine (sin⁻¹) of the value she calculated