4 points
Untitled Question
Kimberly is asked to find mZM. What is her error?
N
sin M _ sin
16 10
sin M=
16.sin 33"
10
16
10
m2M = 0.8714
X Х
33
M
What is Kimberly's error?
A Kimberly did not find the inverse cosine of the value she calculated.
OB. Kimberly did not find the inverse sine of the value she calculated.
OC. Kimberly found the measure of angle N, not M.
D. Kimberly made a computational error.
E Kimberly did not apply the Law of Sines correctly
А

4 points Untitled Question Kimberly is asked to find mZM What is her error N sin M sin 16 10 sin M 16sin 33 10 16 10 m2M 08714 X Х 33 M What is Kimberlys error class=

Respuesta :

Answer:

The error is;

B. Kimberly did not find the inverse sine of the value she calculated

Step-by-step explanation:

The given parameters of the triangle ΔLMN are;

[tex]\overline {LN}[/tex] = 16

[tex]\overline {NM}[/tex] = 10

∠L = 33°

By sine rule, we have;

[tex]\dfrac{sin \ M}{16} = \dfrac{sin \ L}{10} = \dfrac{sin \ N}{\overline {LM}}[/tex]

Given that ∠L = 33°, we have;

[tex]\dfrac{sin \ M}{16} = \dfrac{sin \ 33^{\circ}}{10}[/tex]

Therefore, we have;

[tex]sin \ M = 16 \times \dfrac{sin \ 33^{\circ}}{10} \approx 0.8714[/tex]

sin M ≈ 0.8714

[tex]\therefore m \angle M = sin^{-1} \, (sin \ M)\approx sin^{-1} (0.8714) \approx 60.62^{\circ}[/tex]

Therefore, m∠M ≈ 60.62°

m∠M ≠ sin M ≈ 0.8714

Therefore;

Kimberly did not find the inverse sine (sin⁻¹) of the value she calculated

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